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A shipment of 40 fancy calculators contains 3 defective units. What is the probability if a college bookstore buys 20 calculators out of this shipment and 1 is defective.

User Roidrage
by
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1 Answer

3 votes

Answer:

38.46%

Explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

There are 40 calculators in one shipment, 37 of them good items and 3 of them are defect items. We need to choose 19 good calculators and 1 defect calculator. The number of ways to do that will be:


(37)/(19)*
(3)/(1)= 37!
(37!)/(19!(37-19!)) * (3!)/(1!(3-1)!)= 53017895700

The number of possible ways to choose 20 calculators out of 40 calculators will be:


(40)/(20)=
(40!)/(20!(40-20!))=137846528820

The chance will be: 53017895700/ 137846528820 = 0.3846= 38.46%

User GLK
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