Answer: (a) 0.9858 (b) 0.54
Explanation:
μ = 21.0, σ = 5.4
a) The shape of the sampling distribution would be approximately normal, the mean of the smaple would be 21.0 and standard deviation of the sample would be 0.9859.
S.D = \frac{\sigma }{\sqrt{n}}
S.D = \frac{5.4 }{\sqrt{30}}
S.D = 0.9859
b) The shape of the sampling distribution would be approximately normal, the mean of the smaple would be 21.0 and standard deviation of the sample would be 0.54.
S.D = \frac{\sigma }{\sqrt{n}}
S.D = \frac{5.4 }{\sqrt{100}}
S.D = 0.54
The sample standard deviation would vary becuase as the sample size increases the sample S.D decreases.