Question

For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.4 m away, a diffraction pattern appears. The bright band in the center of the pattern is 7.9 cm wide. What is the width of slide?

Answer 1

The width of slide is 0.092 mm.

Step-by-step explanation:

Given that,

Wave length = 680 nm

Distance between slit and screen D= 5.4 m

Distance of bright band 2y = 7.9 cm

`y =(7.9)/(2)`

`y=3.95\ cm`

We need to calculate the width of slide

Using formula of width

`d=(\lambda D)/(y)`

Where, d = width

D =Distance between slit and screen

y = Distance of bright band

Put the value into the formula

`d=(680*10^(-9)*5.4)/(3.95*10^(-2))`

`d=0.092*10^(-3)\ m`

`d=0.092\ mm`

Hence, The width of slide is 0.092 mm.