Question

g Adjacent rows in the first part of the experiment are found to have potentials of 3.66 V and 4.22 V. If the distance between rows is found to be 0.4 cm, what is the magnitude of the electric field at the location between the rows

Answer 1

`E=140V/m`

Step-by-step explanation:

If the electric field is uniform, the electric field between two points at potentials
`V_1` and
`V_2` which are separated by a distance d will be given by the formula:

`E=(\Delta V)/(d)`

So in our case, we have
`E=(4.22V-3.66V)/(0.004m)=140V/m`