Question

Given the reaction: SO3 (g) + H2O(g) → H2SO4 which proceeds with a yield of 85.0%calculate the amount of sulfur ic acid that is formed when 120.0kg sulfur trioxide is mixed with 32.4kg water

Answer 1

The answer to your question is 124.95 g of H₂SO₄

Step-by-step explanation:

Data

yield = 85%

mass of H₂SO₄ = ?

mass of SO₃ = 120 Kg

mass of H₂O = 32.4 kg

Balanced chemical reaction

SO₃ + H₂O ⇒ H₂SO₄

1.- Calculate the molar mass of the reactants

SO₃ = 32 + (16 x 3) = 32 + 48 = 80 g

H₂O = 2 + 16 = 18 g

2.- Calculate the limiting reactant

theoretical proportion = 80 /18 = 4.44

experimental proportion = 120/32.4 = 3.7

The limiting reactant is SO₃ because the experimental proportion was lower than the theoretical proportion

3.- Calculate the real amount of SO₃

120g ---------------- 100%

x ----------------- 85%

x = (85 x 120)/100

x = 102 g of SO₃

4.- Calculate the mass of H₂SO₄

molar mass of H₂SO₄ = 2 + 32 + 64 = 98 g

80 g of SO₃ -------------------- 98 g of H₂SO₄

102 g of SO₃ -------------------- x

x = (102 x 98)/80

x = 124.95 g of H₂SO₄