Question

If a gas’s [kelvin] temperature doubles and it’s volume then remains the same, then what happens to it’s pressure?

Answer 1

The final pressure will double i.e it will be twice the initial pressure

Step-by-step explanation:

T1 = T

T2 = 2T ( twice the original T)

P1 = P

P2 =?

Since the volume is constant,

P1/ T1 = P2 /T2

P/ T = P2 / 2T

Cross multiply

T x P2 = 2T x P

Divide both side by T

P2 = (2T x P) / T

P2 = 2P

Therefore, the final pressure will double i.e it will be twice the initial pressure