Answer:
The heat input per cycle is closest to 230.8 J
Step-by-step explanation:
Given;
percentage of energy waste = 35%
The lowest cold-reservoir temperature = 15.0°C
useful work done in the reservoir per cycle = 150.0 J
To design an ideal Carnot heat engine that wastes only 35.0% of the heat that goes into it.
If 35% of heat input = wasted work, then
65 % of heat input = useful work
∴ 0.65 × heat input = 150
heat input = 150/0.65
heat input = 230.8 J
Therefore, the heat input per cycle is closest to 230.8 J