Question

Some passengers on an ocean cruise may suffer from motion sickness as the ship rocks back and forth on the waves. At one position on the ship, passengers experience a vertical motion of amplitude 1.0 m with a period of 13 s .

What fraction is this of g?
What is the maximum acceleration of the passengers during this motion?

Answer 1

Step-by-step explanation:

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Answer 2

Answer: 1936/8281 m/ssquare

Maximum acceleration = 0.23m/ssquare

Explanation: using the formular f=1/T, frequency is calculated as 1/13hertz.

But g=(2Πf)square × A

Where Π=pie=22/7, f is the frequency=1/13, and A is the amplitude =1 m .

By insputing the values in the formula, we have g= (2/13×22/7)square × 1

This will give 4/169×22/7×22/7

Which is equal to 1936/8281 m/ssquare

And when divided gives 0.23m/ssquare as the maximum acceleration.