Your question is difficult to understand, that is why I am going to edit your question as follow:
Edited Question:
Cone A and B both have a volume of 48π Cubic units but have different dimensions. Cone A has a radius=6 units and a height=4 units.
Find the one possible radius and height for cone B be to have the same volume as cone A.
Answer:
Radius of cone B= 6units
Height of cone B=units
Explanation:
As we know the formula for the volume of a cone is
![V=\pi\ r^(2)(h)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8jdg8ww0nf89qy0uddwb23x9l52fwnqt2z.png)
If volume of A and Volume B is given as same, thus
![V_(A)=V_(B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/wcggpb3usqrzjaa70ievkned3lo0xghs7c.png)
![\pi\ (R_(A)) ^(2)(H_(A) )/(3) =\pi\ (R_(B)) ^(2)(H_(B) )/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pdyed59jfz4unq7176zbjzameqsrluk2ue.png)
comparing equations above, we get
![R_(A)=R_(B)\\H_(A)=H_(B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/44aabvu7yn6y7l7g1v4qbqzwgp9m4y8iym.png)
Thus, Radius of cone A=6units
and
Height of cone B= 4units