Answer:
mass of air = 324 kg
Step-by-step explanation:
mass of air = moles of air × molecular weight (N₂)
moles of air = PV / RT
Given that
P = 1 atm
Volume of room = 282 m³
R = 0.082L atm mol⁻¹k⁻¹
= (1 × 282 × 10³) / (0.0821 × 297)
= 11.565 × 10³mol
molecular weight of N₂ = 28g/mol
mass of air = (11.565 × 10³)mol × 0.028kg/mol
= 323.8kg
to three significant figures = 324 kg