Question

The angular position of an object moving in a circle is given by the following equation: theta open parentheses t close parentheses equals open parentheses 2 rad over straight s squared close parentheses t squared minus open parentheses 3 rad over straight s cubed close parentheses t cubed What is the angular velocity of the object (in rad/s) at t

Answer 1

`4t-9t^2`

Step-by-step explanation:

`\theta(t) =2t^2-3t^3`

Just like linear velocity is a time-derivative of linear position or displacement, so is angular velocity a time-derivative of angular position or displacement.

`\omega(t) = (d)/(dt)\theta(t) = 4t-9t^2`