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A mass of 2.205 kg of oxygen fills a weighted piston-cylinder device at 105.091 kPa and 43.483 oC. Device is cooled until the temperature is 23.014 oC. Determine the change in volume in liters

User Hoppo
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2 Answers

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Step-by-step explanation:

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A mass of 2.205 kg of oxygen fills a weighted piston-cylinder device at 105.091 kPa-example-1
User Dan Esparza
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Answer:

∆V = -111.6 Liters

Change in Volume = -111.6 Liters

Step-by-step explanation:

From the ideal gas equation,

PV = mRT

V = mRT/P

Change in temperature, results in volume

∆V = mR∆T/P ......1

Where;

P = pressure = 105.091kPa = 105091 Pa

∆V = change in Volume

m = mass = 2.205 kg

R = gas constant for oxygen= 259.84 J/kgK

∆T = change in Temperature = (23.014 - 43.483) = -20.469K

Substituting into the equation 1;

∆V = 2.205×259.84×-20.469/105091 m^3

∆V = -0.1116m^3 × 1000L/m^3

∆V = -111.6 Liters

User Aydya
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