Answer:
Kp = 1.39 x 10⁶
Step-by-step explanation:
The strategy here is to utilize the van´t Hoff relation to calculate Kp at 3 ºC:
ln ( K₂ / K₁ ) = - ΔHºrxn / R x [1/T₂ - 1/T₁]
where K₂ and K₁ are the equilibrium constants at temperatures T₂ and T₁ , ΔHºrxn is the enthalpy change for the reaction and R is the gas constant.
Thus,
Let K₂ equal the equilibrium constant at 3ºC ( 3 + 273 ) K, then:
T₂ = 276 K
T₁ = (25 + 273) K = 298 K ( standard temperature in thermodymics)
ΔHºrxn = -128 kJ/mol x 1000 J /kJ = -1.28 x 10⁵ J / mol
ln ( K₂ / 2.25 x 10⁴ ) = - (-1.28 x 10⁵ J / mol/ 8.314 J/K mol ) x [ 1 / 276 K - 1 / 298 K]
= 4.12
Taking inverse natural log function to both sides of the equation,
K₂ / 2.25 x 10⁴ = e^(4.12)
K₂ = 1.39 x 10⁶