Answer:
Step-by-step explanation:
m(total) = 729 g
m(pure) = 277 g
Mass of impure iron ore sample:
W(impure) - mass percent
W(impure) = m(total) - m(pure) / m(total) = 729 g - 277 g / 729 g
= 0,62 ⇒ 62%
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