Answer:
20%
Explanation:
We have been given that during the the first month, the company received 4,264 phone calls. During the second month, the company received 25% more phone calls than in the first month.
Let us find number of calls received during 2nd month by multiplying 4,264 by 1.25 as
.
![\text{Number of calls in 2nd month}=4264(1.25)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w1147tgwl2v9oqj9iikvyoeojpk727vre7.png)
![\text{Number of calls in 2nd month}=5330](https://img.qammunity.org/2021/formulas/mathematics/high-school/hvysakna8s3cg251qc10xbop10sst571c5.png)
Now, we will use percent increase formula as shown below:
![\text{Percent increase}=\frac{\text{Final value}-\text{Initial value}}{\text{Initial value}}* 100\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/4fg8tmwb8hwxslplwcdt9xr9vd80i5onh8.png)
![\text{Percent increase}=(6396-5330)/(5330)* 100\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/x6t1hplq1r1atk3p0iwgaw7niupki1onhb.png)
![\text{Percent increase}=(1066)/(5330)* 100\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/v0v71f3kfl0xt8ya2ckbu1dl7qti6ih4z2.png)
![\text{Percent increase}=0.2* 100\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/i7ihm9qeb5awfkjgxuhfo9ehk90l1egz0e.png)
![\text{Percent increase}=20\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/lgdspx5dfxd0xma2vjihz1m23wwndkft1k.png)
Therefore, there was a 20% increase in the number of phone calls from the second month to the third month.