Answer:
![p_n = 135(1.05)^n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/e1uc2uj8baay1gg9yajzplfdiydcyb0kc3.png)
Explanation:
In the situation of this problem, we have:
- The initial college's tuition per hour is
![p_0 = 135\$](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5rqe5yxg6a28ct0tq67yefj878dqc35ukz.png)
- Then, we know that the price increases by 5% each year. This means that its value increases by
each year, which is equivalent to
each year
So, after 1 year, the price will be
![p_1 = 1.05 p_0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6lko8dd6yrl3695ten4w73xm6atqj7ig8h.png)
After 2 year, the price will be
![p_2 = 1.05 p_1 = 1.05(1.05 p_0)=1.05^2 p_0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zidnurkpk71n5hodyfhe82jw1hhn5f16fw.png)
So after n years, the price will be
![p_n = 1.05^n p_0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kocaei9inzm5blxcuc4k3fhrmnpp338e06.png)
And by substituting the value of p0, we find the final expression:
![p_n = 135(1.05)^n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/e1uc2uj8baay1gg9yajzplfdiydcyb0kc3.png)
where n is the number of years.