Question

TIMES PLEASE HELP Find the magnitude of vector u shown above. Pic of asnwers and triangle!!

Answer 1

C.
`\vert u \vert = √(29)`

Explanation:

The magnitude of
`u` is given by

`\vert u \vert = √((\Delta x )^2+(\Delta y )^2)`,

and to evaluate this we just need to find
`\Delta x` and
`\Delta y`.

As we see in the graph

`\Delta x = (-4)-1 = -5` (the difference in x-coordinates of
`u`)

and

`\Delta y = (3)- (1)=2`; (the difference in y-coordinates of
`u`)

Therefore,

`\vert u \vert = √((\Delta x )^2+(\Delta y )^2) = √((-5)^2+(2)^2) \\\\\boxed{ \vert u \vert = √(29) }`