Question

1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be the unknown gas?A. CL2B. SF6C. KrD. UF6E. Xe

Answer 1

the species that could be the unknown gas is SF₆

Step-by-step explanation:

Graham's Law of Effusion states that the rate of effusion is inversely proportional to the square root of the molecular mass

hence
`(R_(1) )/(R_(2) ) = \sqrt{(M_(2) )/(M_(1) )}`

But
`2.14= \sqrt{(M_(2) )/(32 )}` where the molar mass of oxygen O₂ = 32 we hava

2.14² = M₂/32 or M₂ = 146.5472

However comparing the likely candidates it is observed that the best canditate is SF₆ as we have Sulphur molar mass = 32 and fluoriine molar mass = 18.99 then

32 + 6×18.99 = 145.95 ≅ 146