Question

A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg was used. Calculate the Brinell hardness (in HB) of this material.

Answer 1

HB=131.69

Step-by-step explanation:

Given that

Diameter , D= 10 mm

Depth of indentation ,d= 1.55 mm

Load ,P =500 kg

Brinell hardness is given as

`HB=(P)/(\pi D(D-√(D^2-d^2)))`

Now by putting the values in the above equation we get

`HB=(500)/(\pi * 10* (10-√(10^2-1.55^2)))`

HB=131.69

Therefore the hardness of the material will be 131.69 HB.