Question

A flask apparatus is composed of 3 round flasks all connected to a single tube through a stopcock in the closed position for each flask. The first flask contains 1.15 L He at 207 torr. The second flask contains 1.15 L Ne at 0.458 atm. The third flask is much larger than the other two and contains 2.45 L at 23.8 kPa. what is the partial pressure of each gas and the total pressure after all the stopcocks are opened?

Answer 1

The partial pressure of Helium (He) is 0.234 atm

The partial pressure of Neon (Ne) is 0.234 atm

The partial pressure of gas in the third flask is 0.497 atm

The total pressure of the gas is 0.965 atm

Step-by-step explanation:

First flask

V1 = 1.15 L

P1 = 207 torr = 207/760 = 0.272 atm

Second flask

V2 = 1.15 L

P2 = 0.458 atm

Third flask

V3 = 2.45 L

P3 = 23.8 kPa = 23.8/101.325 = 0.235 atm

Total pressure (Pt) = P1 + P2 + P3 = 0.272 + 0.458 + 0.235 = 0.965 atm

Total volume (Vt) = V1 + V2 + V3 = 1.15 + 1.15 + 2.45 = 4.75 L

Partial pressure of He = V1/Vt × Pt = 1.15/4.75 × 0.965 = 0.234 atm

Partial pressure of Ne = V2/Vt × Pt = 1.15/4.75 × 0.965 = 0.234 atm

Partial pressure of gas in the third flask = V3/Vt × Pt = 2.45/4.75 × 0.965 = 0.497 atm