Question

Question 21

0.1 pts
Given the following equation:
2 Al(s) +3 FeO(s) 3Fe(s)+ Al2O3(s)
How many moles of aluminum are needed to react completely with 1.2 moles of
FeO?
24n
1.2 n
oooo
8n
1.6n

Answer 1

`\large \boxed{\text{0.8 mol of Al}}`

Step-by-step explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

2Al + 3FeO ⟶ 3Fe + Al₂O₃

n/mol: 1.2

2 mol of Al react with 3 mol of FeO

`\text{Moles of Al} = \text{1.2 mol Fe}* \frac{\text{1 mol Al }}{\text{3 mol Fe}}= \textbf{0.8 mol Al}\\\\\text{The reaction will need $\large \boxed{\textbf{0.8 mol of Al}}$}`