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1.5mol C3H8 from C3H8+5O2-->3CO2+4H2O .how many grams of carbon dioxide are produced

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Answer:


\large \boxed{\text{200 g CO}_{{2}}}

Step-by-step explanation:

We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

Mᵣ: 44.01

C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol: 1.5

1. Calculate the moles of CO₂

The molar ratio is 3 mol CO₂:1 mol C₃H₈


\rm \text{Moles of CO}_(2) = \text{1.5 mol C$_(3)$H}_(8) * \frac{\text{3 mol CO}_(2)}{\text{1 mol C$_(3)$H}_(8)} =\text{4.5 mol CO}_(2)

2. Calculate the mass of CO₂.


\text{Mass of CO}_(2) = \text{4.5 mol CO}_(2) * \frac{\text{44.01 g CO}_(2)}{\text{1 mol CO$_(2)$}} = \textbf{200 g CO}_{\mathbf{2}}\\\text{The reaction will form $\large \boxed{\textbf{200 g CO}_{\mathbf{2}}}$}

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