Question

Answer the questions in the image.

Answer 1

1. 63.62 in².

2. 16 in².

3. 47.62 in².

4. 0.25 .

5. 0.74 .

Explanation:

1.

Solution,

Given,

Diameter = 9 inch.

Now,

Area = πr²

Diameter = r²

Then,

Area = 1/4 πd²

= 1/4 π9²

= 63.62 in².

2.

Solution,

Given,

Length of a Side = 4 inch.

Now,

Area = L²

= 4²

= 16 in².

3.

Solution,

Given,

Area of the Circle = 63.62 in².

Area of the Square = 16 in².

Now,

Area of The White Part of the Circle = Area of Circle - Area of Square

= 63.62 in² - 16 in².

= 47.62 in².

4.

Solution,

Given,

Area of the Square = 16 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the Square = Square Area / Circle Area

= 16 / 63.62

= 0.25 .

5.

Solution,

Given,

White Part of the Circle = 47.62 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the white Part = White Area / Circle Area.

= 47.62 / 63.62

= 0.74 .

Answer 2

#1

• Radius=9/2=4.5in

Area:-

• πr²
• 4.5^2π
• 20.25πin^2
• 63.58in^2

#2

• Side=a=4in

Area:-

• a²
• 4²
• 16in^2

#3

Area of the white part=Area of circle-Area of square

• 63.585-16
• 47.585in^2

#4

Probability

• 16/63.585
• 0.252

#5

Probability

• 47.58/63.585
• 0.75