Question

Find the midpoint of BF B(0,-14) F(4,6)

Answer 1

Explanation:

B(0, -14) ⇒ x₁ = 0 & y₁ = -14

F(4,6) ⇒ x₂ = 4 & y₂ = 6

`Midpoint = \left((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2) \right)`

`=\left((0+4)/(2),(-14 + 6)/(2)\right)\\\\\\= \left((4)/(2), (-8)/(2) \right)\\\\\\=\left(2, -4 \right)`