Question

A 63 gram piece of magnesium absorbs 6689 joules of heat. The final temperature is 663 degrees Celsius. What was the initial temperature? ( the specific heat of magnesium is 1.023 j/g degrees Celsius)

Answer 1

`559^(\circ)C`

Step-by-step explanation:

When heat is supplied to a substance, the temperature of the substance increases according to:

`Q=m C (T_f-T_i)`

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

`T_i` is the initial temperature

`T_f` is the final temperature

For the sample of magnesium in this problem, we have:

m = 63 g is the mass

Q = 6689 J is the hear supplied

C = 1.023 J/gC is the specific heat capacity

`T_f=663^(\circ)C` is the final temperature

Solving the formula for
`T_i`, we find the final temperature:

`T_i = T_f-(Q)/(mC)=663-(6689)/((63)(1.023))=559^(\circ)C`