The question is incomplete as it does not have the option which are:
A). All of their daughters must be color blind..
B). Some of their sons can have normal color vision..
C). Their daughters might carry a gene for color blindness.
D). All of their sons will carry a gene for color blindness.
Answer:
Option-B and C are correct
Step-by-step explanation:
The gene for color blind is located on the X chromosome which is passed on to the progeny during sexual reproduction.
Since the disease is a recessive trait therefore in mothers the gene expresses themselves when both the chromosome contains the allele that is during homozygous condition.
In males, since one Y chromosome is present therefore only one copy of the chromosome carrying the allele will cause disease.
- The heterozygous females (XcX) -the carrier of the disease
- The homozygous females (XcXc) -the affected females.
- The boy with genotype- (XcY) will be affected males
- The boy with (XY) will be normal males.
In the given question, the cross between the normal color vision genotype- XcX and affected male that is XcY is performed.
Xc X
Xc XcXc XcX
Y XcY XY
This shows that the their daughter might carry gene for color blindness (XcX) and their son ca have normal vision (XY).
Thus, Option-B is the correct answer.