Answer:
d. 0V
Step-by-step explanation:
The magnitude of four point charges are +3q, -q, +2q and -4q. I think you forget to mention the signs.
As we know that the potential due to the point charge that has traveled the distance d can be represented mathematically as,
![V = k(q)/(r)](https://img.qammunity.org/2021/formulas/physics/college/z3ojff3faeu4ce2yyycldj4w2fgaz415cr.png)
= 1/4λε = 9×
Nm²/C²
Now as it is mentioned in the question that all four charges are arranged in the corners of a square so there distance from the center is same. We can rewrite the above potential equation as follows.
(1)
We can find out d by the pythagoras theorem, as we are dealing with square so d is a semi diagonal.
![d = \sqrt{(L^(2) )/(4)+(L^(2) )/(4) } = (√(2) )/(2) L](https://img.qammunity.org/2021/formulas/physics/college/ken1re0i7f7012v2vb6gnvzvxlg6vbifsv.png)
by putting all values in equation (1)
V =
![(9*10^(9) )/((√(2) )/(2) L ) (+3q-q+2q-4q)](https://img.qammunity.org/2021/formulas/physics/college/cnqrd52ingv4jtl4baxl8ghsm4b8y0fcvo.png)
V = 0V