Question

At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M-1s-1 :2SO3g --> 2SO2g + O2g Suppose a vessel contains SO3 at a concentration of 1.44M. Calculate the concentration of SO3 in the vessel 0.240 seconds later. You may assume no other reaction is important.

Answer 1

0.245M

Step-by-step explanation:

2SO3g --> 2SO2g + O2g

Rate Constant, k = 14.1 M-1s-1

Initial Concentration, Ao = 1.44M

Final Concentration, A = ?

time = 0.240s

The integrated rate law for second order reactions relating these parameters is given as;

1 / [A] = kt + 1 / [A]o

1 / [A] = (14.1 * 0.240) + 1 / 1.44

1 / [A] = 3.384 + 0.694 = 4.078

[A] = 1 / 4.078 = 0.245M