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How much charged is required to reduced 2 moles of cr6+ to cr3+

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Answer:

6e⁻

Step-by-step explanation:

Charge in reducing 2 mole of Cr⁶⁺ to Cr³⁺

Cr⁶⁺ + xe⁻ → Cr³⁺

The numbers 6+ and 3+ on the chromium atoms are the oxidation number of the atom.

It shows the number of electrons that has been lost by chromium in an oxidation state.

Cr⁶⁺ shows that it has lost 6 electrons. When an atom loses electrons, the number of protons becomes more. This makes it positively charged in nature.

This analogy goes for Cr³⁺

Therefore, in going from reactants to products, chromium

6+ → 3+

In this kind of expression, the number of atoms must be conserved and the charges too;

2Cr⁶⁺ + xe⁻ → 2Cr³⁺

given 2 moles of Cr;

To balance the charge;

2(6+) + x(-) = 2(3+)

12 - x = 6

x = 6

A charge of 6e⁻ is required to reduce 2 mole of Cr⁶⁺ to Cr³⁺

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