Question

An amoeba has 1.00×1016 protons and a net charge of 0.300 pC. (a) How many fewer electrons are there than protons? (b) If you paired them up, what fraction of the protons would have no electrons?

Answer 1

Step-by-step explanation:

(a) It is known that charge on a proton is equal to
`1.6 * 10^(-19) C`. And, net charge is given as
`0.3 pC` which is also equal to
`0.3 * 10^(-12)C`.

Therefore, we will calculate the number of electrons as follows.

`(0.3 * 10^(-12)C)/(1.6 * 10^(-19)C)`

=
`1.87 * 10^(6)`

Hence, there are
`1.87 * 10^(6)` fewer electrons are there than protons.

(b) Now, we will calculate the fraction of protons that would have no electrons as follows.

`(1.88 * 10^(6))/(1 * 10^(16))`

=
`1.88 * 10^(-10)`

Therefore, fraction of the protons that would have no electrons is
`1.88 * 10^(-10)`.