Answer:
ε = 47 %
W = 1645 J
Qc = 1855 J
Step-by-step explanation:
(a) The maximum thermal efficiency of an engine operating between two temperatures, Th and Tc ( hot and cold) is given by:
ε = 1 - Tc/Th
Substituting the values for our question:
ε = 1 - 300K/570K = 47 %
(b) The maximum efficiency just calculated relates to the work and heat as:
ε = W/Qh
where W is work, and Qh is the heat of the hot reservoir which is our energy input and W is the work extracted.
ε = W/Qh ⇒ W = ε x Qh = 0.47 x 3500 J = 1645 J
The energy transferred to the cold reservoir is givern by:
Qh - Qc = W ⇒ Qc = Qh - W = 3500 J - 1645 J = 1855 J