Answer:
The correct answer is 1 x 10⁻⁵
Step-by-step explanation:
In order to solve the problem, we can use the Henderson-Hasselbach equation to find the ratio alanine-COOH/alanine-COO⁻ (amino acid species with carboxylic acid protonated) and the ratio alanine-NH₂/alanine-NH₃⁺ (amino acid species with amino group neutral):
Henderson-Hasselbach equation:
![pH= pKa + log ([A^(-) ])/([HA])](https://img.qammunity.org/2021/formulas/biology/college/zgpg7kkr5pnh9pz3sr006w30sge4sob71g.png)
For carboxylic acid group (pKa= 3) at pH 7:
![7 = 3 + log ([Ala-COO^(-) ])/([Ala-COOH])](https://img.qammunity.org/2021/formulas/biology/college/smswf4mbbk8skno8y0fonvwulnf192sgwp.png)
![4= log ([ Ala-COO^(-) ])/([Ala-COOH])](https://img.qammunity.org/2021/formulas/biology/college/bbfx8yiu8ejx1sk8eaf97focvns30bvn1u.png)
![10^(4) = ([Ala-COO^(-) ])/([Ala-COOH ])](https://img.qammunity.org/2021/formulas/biology/college/b61ea2whg3h9rljj6oap7cq4dnb8l33kf4.png)
We need the ratio of species with protonated carboxylic acid group, so we need the inverse:
![10^(-4)= ([Ala-COOH ])/([Ala-COO^(-) ] )](https://img.qammunity.org/2021/formulas/biology/college/nf78cl20tq5p6bc4g652zgm93qvfgqxmfm.png)
For amino group (pKa= 8) at pH 7:
![7= 8 + log ([Ala-NH_(2) ])/([Ala-NH_(3) ^(+) ])](https://img.qammunity.org/2021/formulas/biology/college/6nwybnwt6leq8vf3y7xkc0luguypk65jqy.png)
![-1= log ([ Ala-NH_(2) ])/([Ala-NH_(3) ^(+) ])](https://img.qammunity.org/2021/formulas/biology/college/afehlcd49ynwmmlm6tk95x3c82uk7kpxhj.png)
![10^(-1) = ([Ala-NH_(2) ])/([Ala-NH_(3) ^(+) ])](https://img.qammunity.org/2021/formulas/biology/college/oywp8rfcalxyenlbhkwrdloe2bj1gnvdqb.png)
Finally, to find the ratio of neutral species we multiply the ratios:
X
= 10⁻⁴ x 10⁻¹= 10⁻⁵