Question

7) The maximum horizontal distance a boy can throw a ball is 50.0 m. Assume he can throw with the same initial speed at all angles. How high does he throw the ball when he throws it straight upward?

Answer 1

Given: v is constant at any value and x=50 m, then find the maximum hieght which is
`y_(max)`. We can also see that the motion of horizontal direction is given by
`x=v_(x)t`, and also, since
`v_(x)=v_(i)` it's
`v_(i)t=50`, also
`t_(1)=(t)/(2)`. So now just put this in the equation
`y_(max)=v_(yi)+(1)/(2)gt^(2)_(1)` you will get ymax being 12.6 along with using the equation
`v_(yf)=v_(yi)-gt_(1)`.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺❀❤