Question

The question is below:

Answer 1

Hello There!!

Given

`3(x - 2) + 7x = (1)/(2) (6x - 2)`

Solving It

`3(x - 2) + 7x = (1)/(2) (6x - 2) \\ \\ \implies3x - 6 + 7x = ([(1)/(2) * 6 \: x] - [(1)/(2) * 2]) \\ \\ \implies10x - 6 = ([(1)/( \cancel2) * \cancel 6 \: x] - [(1)/( \cancel2) * \cancel2]) \\ \\ \implies 10x - 6 = 3x - 1 \\ \\ \fbox{Bringing (3x )to left side whereas( - 6 )in right side} \\ \\ \implies10x - 3x = - 1 + 6 \\ \\ \implies7x = 5 \\ \\ \therefore x = (5)/(7)`

The Solution is =
`(5)/(7)`

`\text\red{One Solution set is possible.}`

Hope This Helps