Question

It is weigh-in time for the local under-85-kg rugby team. The bathroom scale used to assess eligibility can be described by Hooke’s law and is depressed 0.75 cm by its maximum load of 120 kg. (a) What is the spring’s effective spring constant? (b) A player stands on the scales and depresses it by 0.48 cm. Is he

Answer 1

Step-by-step explanation:

Depression = .75 x 10⁻² m

Load = 120 g

Spring constant = 120g / .75 x 10⁻²

= 160 x 10² g / m

b )

Depression by player

= .48 x 10⁻² m

His weight

= .48 x 10⁻² x 160 x 10² g

= 76.8 kg

So he is eligible.