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Which is the product?

6p3 + 23p2 + 9p + 28
6p3 – 23p2 – 9p + 28
6p3 – 23p2 + 9p + 28
6p3 + 23p2 – 9p + 28

User Maldus
by
3.1k points

2 Answers

2 votes

Answer:

c ;)

Step-by-step explanation:

User Anujith
by
3.3k points
4 votes

Question:

Iliana multiplied 3p – 7 and 2p^2 – 3p – 4. Her work is shown in the table.

Which is the product?

6p^3 + 23p^2 + 9p + 28

6p^3 – 23p^2 – 9p + 28

6p^3 – 23p^2 + 9p + 28

6p^3 + 23p^2 – 9p + 28

Answer:

Option C:
6 p^(3)-23 p^(2)+9 p+28 is the correct answer.

Step-by-step explanation:

The two expressions are
3 p-7 and
\left2 p^(2)-3 p-4\right

The product of the expression can be determined by multiplying each of the first term with the second term of the expression, we get,


(3 p-7)\left(2 p^(2)-3 p-4\right)


3 p \cdot 2 p^(2)+3 p(-3 p)+3 p(-4)+(-7) \cdot 2 p^(2)+(-7)(-3 p)+(-7)(-4)

Simplifying we have,


6p^3-9p^2-12p-14p^2+21p+28

Adding the like terms, we have,


6 p^(3)-23 p^(2)+9 p+28

Thus, the product of the two expression is
6 p^(3)-23 p^(2)+9 p+28

Hence, Option C is the correct answer.

User Pachanga
by
3.4k points