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Right equation of the line that is perpendicular to the line Y equals negative 3X +8 and passes through the point -2, 3. Right equation in point slope form

User JANVI
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1 Answer

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hello!

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Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

In this case, we take
\boxed{-3}, change its sign:


\boxed{3}

3 can also be written as


\boxed{(3)/(1) }

Now the numerator & denominator switch places:


\boxed{(1)/(3)}

So that's the slope of the new line.

Now, let's write the equation in point-slope form:-


\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}

Where

y₁ is the y-coordinate of the point (in this case, y₁ = 3)

m = slope (1/3)

x₁= the x-coordinate of the point (in this case, it's -2)

Plug in the values:-


\bigstar{\boxed{\pmb{y-3=(1)/(3)(x-(-2)}}


\bigstar{\boxed{\pmb{y-3=(1)/(3)(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}

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note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

User Dracarys
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