2x + 3y = 15 x + y = 6 work out x and y

Question

asked Dec 8, 2023 2.8k views

1 Answer

Jos Dirksen · Answer 1 · 2023-12-15T06:18:53+0000

Here we have been given with two equations and we will solve them by substitution by elimination method.

Transposing y in 1st equation from L.H.S. to R.H.S. it would be negative,

$\implies \: \displaystyle\sf{x \: = \: 6 - y}$

Now, we would substitute this value of x in Equation No 1.

$\implies \: \displaystyle\sf{2 \: (6 - y) \: = \:15 }$

$\implies \: \displaystyle\sf{2 \: * (6 - y) \: = \:15 }$

$\implies \: \displaystyle\sf{12 - 2y \: = \:15 }$

Transposing 12 to R.H.S.,

$\implies \: \displaystyle\sf{ - 2y \: = \:15 - 12 }$

$\implies \: \displaystyle\sf{ - 2y \: = \:3}$

$\implies \: \displaystyle\bf{ y \: = \: - (3)/(2) }$

Therefore, value of y is - 3/2.

★ Finding out value of x:-

$\implies \: \displaystyle\sf{x \: = \: 6 - y }$

$\implies \: \displaystyle\sf{x \: = \: 6 - ( ( - 3)/( 2) )}$

$\implies \: \displaystyle\sf{x \: = \: (12 + 3)/(2) }$

$\implies \: \displaystyle\bf{x \: = \: (15)/(2) }$

Henceforth,