Answer: incomplete question
Complete question:
A buoy floating in the sea is bobbing in simple harmonic motion with period 1 second and amplitude 11 in . Its displacement d from sea level at time t=0 seconds is 0in, and initially it moves downward. (Note that downward is the negative direction.). Give the equation modelling displacement(d) as a function of time(t)
Answer:
d = -11sin2πt
Explanation:
Given,
Amplitude = 11 in
Period = 1 seconds.
Since, d at t = 0 in
Let displacement be d =asin(wt+∅)
So, a = amplitude = -11 in (it moves downward)
w = angular velocity
= 2π/period
= 2π/1
= 2πrad/sec
Therefore, at t = 0
So, since sin(∅) = 0
∅ = 0
So, inputing values of a,∅, and w we get
d = -11sin(2πt + 0)
d = -11sin2πt