Question

The container of orange juice held 5 and one-third cups of juice. If a serving of orange juice is Start Fraction 7 Over 8 End Fraction of a cup of orange juice, to the nearest whole serving, how many servings were in the container?

Answer 1

Number of servings:
`6(2)/(21)`

Explanation:

In this problem, we have a container of orange juice helding a total of

`C=5(1)/(3)`

cups of juice.

We can re-write this mixed fraction as improper fraction, and we get:

`C=(5\cdot 3 +1)/(3)=(16)/(3)`

We also know that a serving of orange juice is equal to

`s=(7)/(8)`

of cup of orange juice.

Here we want to find how many servings are in the container: to find that, we have to divide the total amount of orange juice in the container (C) by the amount of juice per serving (s), so we find:

`n=(C)/(s)=(16/3)/(7/8)=(16)/(3)\cdot (8)/(7)=(128)/(21)=6(2)/(21)`