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The container of orange juice held 5 and one-third cups of juice. If a serving of orange juice is Start Fraction 7 Over 8 End Fraction of a cup of orange juice, to the nearest whole serving, how many servings were in the container?

User ArthurGuy
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1 Answer

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Answer:

Number of servings:
6(2)/(21)

Explanation:

In this problem, we have a container of orange juice helding a total of


C=5(1)/(3)

cups of juice.

We can re-write this mixed fraction as improper fraction, and we get:


C=(5\cdot 3 +1)/(3)=(16)/(3)

We also know that a serving of orange juice is equal to


s=(7)/(8)

of cup of orange juice.

Here we want to find how many servings are in the container: to find that, we have to divide the total amount of orange juice in the container (C) by the amount of juice per serving (s), so we find:


n=(C)/(s)=(16/3)/(7/8)=(16)/(3)\cdot (8)/(7)=(128)/(21)=6(2)/(21)

User Immortal Blue
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