Question

A 0.1 kg block of brass is cooled until it releases 56.4 J of heat. If the temperature of the block was 5 K initially, what is it now?

Answer 1

3.5 K

Step-by-step explanation:

When a sample of a substance releases heat energy, its temperature decreases according to the equation:

`Q=mC(T_f-T_i)`

where

Q is the heat energy released

m is the mass of the substance

C is the specific heat capacity

`T_i` is the initial temperature

`T_f` is the final temperature

For the block of brass in this problem, we have:

m = 0.1 kg is the mass

Q = -56.4 J is the heat energy released (negative since it is released)

C = 380 J/kg K is the specific heat capacity of brass

`T_i=5 K` is the initial temperature

Solving for
`T_f`, we find the final temperature:

`T_f=T_i + (Q)/(mC)=5+(-56.4)/((0.1)(380))=3.5 K`