Answer:
The expected number of contracts the sales representative will get this week is 5.22
Explanation:
For each client, there are only two possible outcomes. Either there is a sales contract, or there is not. The probability of having a sale contract with each client is independent of other clients. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
![E(X) = np](https://img.qammunity.org/2021/formulas/mathematics/college/66n16kmn896qth698tyf6rfu48vhaipkmv.png)
In this problem, we have that:
![n = 18, p = 0.29](https://img.qammunity.org/2021/formulas/mathematics/college/ninhqi00vt2t2w3737lqfzsbhr8vnumel6.png)
What is the expected number of contracts the sales representative will get this week?
![E(X) = np = 18*0.29 = 5.22](https://img.qammunity.org/2021/formulas/mathematics/college/zmuulv00lf6n7ra11wnyel9hk2lnrhklnn.png)
The expected number of contracts the sales representative will get this week is 5.22