Question

At what temperature (in Kelvin) will the diffusion coefficient for the diffusion of species A in metal B have a value of 6.48 × 10-15 m2/s, assuming values of 4.0 × 10-5 m2/s and 230,000 J/mol for D0 and Qd , respectively?

Answer 1

= 1227.9K

Step-by-step explanation:

Given that,

D₀ = 4.0 x 10⁻⁵ m²/s,

Qd = 230,000 J/mol,

D = 6.48 x 10⁻¹⁵ m²/s

Gas constant R = 8.31 J/mol-K

T =
`-(Q_d)/(R* (InD - IND_0))`

=
`-(230000)/(8.31* (In(6.48 * 10^-^1^5) - In(4.0 * 10^-^5))`

=
`(-230000)/(-187.307)`

= 1227.93K

≅1227.9K