Question

A 10.0 g insulating sphere with a net charge of +2.0 nC is suspended between two plates of a charged, square capacitorof sides 10 cm and plate separation 10 cm. What is the charge on the top capacitor plate?

Answer 1

= 4.34 × 10⁻⁶C

Step-by-step explanation:

Net Force = W - F(electric) = 0

where , F(electric) = qE

qE = qV/d

V = potential between plate

V = Q/C

Q = charge on plate

C = capacitance

C = E₀A / d

F(electric) = qQ/E₀A

W = F(electric)

mg = qQ/E₀A

Q = mgE₀A / q

(A) area of plate = (0.10m)² = 0.01m²

m = 10 × 10⁻³kg

E₀ = 8.85 × 10⁻¹²C²N⁻¹m⁻²

q = 2 × 10⁻⁹c

Q =((10 × 10⁻³)(9.8)(8.85× 10⁻¹²)(0.01)) / (2 × 10⁻⁹)

Q = 4.34 × 10⁻⁶C