Question

the chef mixed a seasoning that costs $3 per ounce with a seasoning that costs $1.75 per ounce to create a 24-ounce mixture that costs $2 per ounce. how many ounces of the $3 per ounce seasoning did he use?

Answer 1

4.8 ounces

Explanation:

X= number of ounces for the $3.00 mixture of seasoning

$3.00/OZ + $1.75/ OZ = $2.00/ OZ We are adding the seasonings together to produce the 24 OZ mixture

X + 24-X = 24OZ To get the missing term we will subtract what we have from X

100 [(3.00)(X) + (1.75)(24-X)] = [(2.00)(24)] 100 to get rid of the decimals multiply both sides by 100

(300)(X) + (175)(24-X) = (200)(24) Multiply on each side, removing the parenthesis

300X + 4,200 - 175x = 4,800 Get all of the X's on one side of the equation remember to change the sign of 4,200

300X - 175X = 4,800 - 4,200 Combine Like Terms

125X = 600 Get X alone

125 125 To get X, we will divide both sides by 125

X = 4.8 OZ

The chef used 4.8 ounces of the $3.00 seasoning