79.9k views
25 votes
Find the equation of the line that is perpendicular to the line Y equals negative 4X -4 and passes through the point -2, -4. Write the equation in point slope form

1 Answer

3 votes

hello!

======================================================

Perpendicular lines have slopes that are opposite reciprocals.

This means we take the slope, flop it over, and change its sign.

In this case, we have


\boxed{-4}

First, flop it over:


\boxed{-(1)/(4)}

Change its sign:


\boxed{(1)/(4)}

Now, let's write the equation of the line in point-slope form:-


\bigstar\boxed{\pmb{y-y1=m(x-x1)}}\longleftarrow\sf{Point-Slope~Formula}

Where

y₁ is the y-coordinate of the point that the line intersects

m is the slope of the line

x₁ is the x-coordinate of the point that the line intersects

In this case,

y₁ is equal to -4

m is equal to
\boxed{(1)/(4) }

x₁ is equal to -2

Plug in the values:-


\bigstar{\boxed{y-(-4)=(1)/(4)(x-(-2)}

Simplify:-


\longrightarrow\sf{y+4=(1)/(4) (x+2)

and we're done!

===========================================================

note:-

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

User QTom
by
8.7k points