Question

An elevator cab has a mass of 4710 kg and can carry a maximum load of 1910 kg. If the cab is moving upward at full load at 3.80 m/s, what power is required of the force moving the cab to maintain that speed?

Answer 1

Power P=246.78 KW

Step-by-step explanation:

Mass of Elevator=4710 Kg

Can carry load =1910 Kg

Total Mass m to be lifted =4710 kg + 1910 Kg =6620 kg

speed = 3.80 m/s ⇒ per second distance traveled (height h) = 3.80 m and time t = 1 s

Using formula of Power P =
`(work)/(time)`

P =
`(mgh)/(t)`

P= 6620kg × 9.81 m/s² × 3.80 m / 1s

P= 246780.36 W

P=246.78 KW