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The product of three integers is –216, but their sum is –23. Which of the following is not one of these three numbers? -2 -12 -6 -9

User Javy
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Answer:

We can conclude that -6 is not one of these three numbers. So, the actual numbers are:


  • \left(-2\right)+\left(-12\right)+\left(-9\right)=-23

  • \left(-2\right)* \left(-12\right)* \left(-9\right)=-216

Explanation:

  • The product of three integers is –216.
  • Their sum is –23.

Considering the given numbers

-2 -12 -6 -9

Lets take the three numbers

-2 -12 -9

Taking the sum of -2 -12 -9


\left(-2\right)+\left(-12\right)+\left(-9\right)


\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a


=\:-2-12-9


=-23

Therefore, the sum of -2 -12 -9 is -23.

i.e.


\left(-2\right)+\left(-12\right)+\left(-9\right)=-23

Taking the product of -2 -12 -9


\left(-2\right)* \left(-12\right)* \left(-9\right)


\mathrm{Apply\:rule\:}\left(-a\right)* \left(-b\right)\:=\:a* \:b

as


\left(-2\right)* \left(-12\right)=2* \:12=24

so


=24* \left(-9\right)


\mathrm{Apply\:rule\:}a* \left(-b\right)\:=\:-a* \:b


24* \left(-9\right)=-24* \:9=-216

Therefore, the product of -2 -12 -9 is -216.

i.e.


\left(-2\right)* \left(-12\right)* \left(-9\right)=-216

Thus, we can conclude that -6 is not one of these three numbers. So, the actual numbers are:


  • \left(-2\right)+\left(-12\right)+\left(-9\right)=-23

  • \left(-2\right)* \left(-12\right)* \left(-9\right)=-216
User Wwwslinger
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