Answer:
Given info: The surface area of teapot plated with silver is 700 cm2700 cm2, the cell is powered by 12.0-V12.0-V, the resistance of the cell is 1.80 Ω1.80 Ω, thickness of silver layer is 0.133-mm0.133-mm and density of silver is 10.5×103 kg/m310.5×103 kg/m3.
Write the expression for the mass of the silver.
m=ρAdm=ρAd (1)
Here,
ρρ is the density of silver.
AA is the surface area.
dd is the thickness of the silver layer.
Substitute 10.5×103 kg/m310.5×103 kg/m3 for ρρ, 700 cm2700 cm2 for AA and 0.133-mm0.133-mm for dd in equation (1) to find mass of the silver.
m=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 gm=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 g
Thus, the mass of silver is 97.8 g97.8 g.
Write the expression for number of moles of silver.
n=mWan=mWa (2)
Here,
mm is the mass of silver.
WaWa is the atomic weight.
The atomic weight of silver is 107.8 g/mole107.8 g/mole
Substitute 97.8 g97.8 g for mm, and 107.8 g/mole107.8 g/mole for WaWa in equation (2) to find number of moles of silver.
n=97.8 g107.8 g/mole=0.907 moln=97.8 g107.8 g/mole=0.907 mol
Thus, the number of moles of silver is 0.907 mol0.907 mol.