Question

If Ed​ Lusk, VP for​ operations, proceeds with the existing prototype​ (option a), the firm can expect sales to be 110 comma 000 units at ​$580 ​each, with a probability of 0.65 and a 0.35 probability of 65 comma 000 at ​$580. ​If, however, he uses the value analysis team​ (option b), the firm expects sales of 85 comma 000 units at ​$740​, with a probability of 0.62 and a 0.38 probability of 60 comma 000 units at ​$740. Value​ engineering, at a cost of ​$100 comma 000​, is only used in option b. Which option has the highest expected monetary value​ (EMV)?

Answer 1

Option b has the highest expected monetary value​ (EMV)

Step-by-step explanation:

For Option a:

At probability 0.65: At probability 0.35

Units=110,000 Units=65,000

Amount=$580 each Amount=$580

EMV/Total Sales=0.65(110,000*580)+0.35(65,000*580)

EMV/Total Sales=$54,665,000

For Option b:

At probability 0.62: At probability 0.38

Units=85,000 Units=60,000

Amount=$740 each Amount=$740

EMV/Total Sales=0.62(85,000*740)+0.38(60,000*740)

EMV/Total Sales=$55,870,000

So Option B has the highest expected monetary value​ (EMV).